64x^2+80x-39=0

Solution for 64x^2+80x-39=0 equation:

64x^2+80x-39=0

a = 64; b = 80; c = -39;
Δ = b2-4ac
Δ = 802-4·64·(-39)
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16384}=128$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-128}{2*64}=\frac{-208}{128}
=-1+5/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+128}{2*64}=\frac{48}{128}
=3/8
$